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2.5x^2-20x+40=0
a = 2.5; b = -20; c = +40;
Δ = b2-4ac
Δ = -202-4·2.5·40
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{20}{5}=4$
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